### move question with answer to appropriate section

 ... ... @@ -35,6 +35,7 @@ - otherwise *biaxial* (more complicated) - Constraint on $s$: - $s$ defined by limiting process $L → 0$ and the constants $a, b, c$ - To make spectral representation of $Q$ fit to $Q = s(n ⊗ n - \tfrac13 \operatorname{Id})$, we need $s = -3 λ_1 = -3 λ_2, n = ê_3$. With $s$ depending on $a, b, c$ (see formula (3) on page 3 (=495)), $Q$ is further reduced to the choice of $n$. That is what we assumed as our model at the beginning. - but also $Q$ has an original definition via $μ$. Together: math Qn · n ... ... @@ -172,11 +173,6 @@ Let $Q ∈ W^{1,p}(Ω, 𝒬), 1 ≤ p ≤ ∞$ be non-orientable. Then there e - conversion between energy functionals possible ## Questions - What is the third index $k$ for $Q$ on page 3 (= 495)? - Probably it's a derivative of $Q_{ij}$ in direction $k$. - And why is it written as a product instead of a square$^2$? - To make spectral representation of $Q$ fit to $Q = s(n \otimes n - \tfrac13 \operatorname{Id})$, we need $s = -3 λ_1 = -3 λ_2, n = ê_3$. How can $s$ then depend on $a, b, c$ (see formula (3) on page 3 (=495))? If that's the case, $Q$ is further reduced to the choice of $n$ but that's what we assumed as our model at the beginning. So apparently that's fine. - in Proposition 1 it should be $\det Q = +\frac{2s^3}{27}$ since the $-$ exists in exactly two eigenvalues: $\det Q = λ_1 λ_2 λ_3 = (-\frac s3)(-\frac s3)(+\frac {2s}3) = +\frac{2s^3}{27}$. Correct? ## Errors in the paper p.5 (=497) Proposition 1 (iii): sign of $\operatorname{det} Q`$ is wrong. Must be positive, since exactly two of the eigenvalues are negative ... ...